DAY 3
    
    In day 3, teacher Ver discussed determining a function whether it is a Domain or Range.

    Example :

a. x² + 2y - 1 = 0

b .1/2x + 3y + 5  

  

  a. In terms of x.                           

x² = -2y + 3

x = √-2y + 3

D = { x / x ∈ R }

 In terms of y.

2y =  -x² + 3 
2            2

y = -x² + 3
            2
R = { y / y ≤  1

b. In terms of x.

 [1x = -3y - 5] 2
   2
 x = -6y - 10

D: { x / x ∈R }

  In terms of y.

[3y = -1/2x - 5] 2

6y = x - 10
            6

R: { y / y ∈R }